If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
(a+b)^2 = 0
(a+b)^2 = 0
(a+b)^2 = 0
x in (-oo:+oo)
a^2-(a*((b^2)/((a+b)^2)))+b/a-b = 0
(-1*a*b^2)/((a+b)^2)+a^2+b/a-b = 0
(-1*a^2*b^2)/(a*(a+b)^2)+(a*a^2*(a+b)^2)/(a*(a+b)^2)+(b*(a+b)^2)/(a*(a+b)^2)+(a*(-b)*(a+b)^2)/(a*(a+b)^2) = 0
a*a^2*(a+b)^2+b*(a+b)^2+a*(-b)*(a+b)^2-1*a^2*b^2 = 0
a^5-(a^2*b^2)+a^3*b^2+2*a*b^2+2*a^4*b+a^2*b+b^3-(a*b^3)-2*a^2*b^2-(a^3*b) = 0
a^5+a^3*b^2+2*a*b^2+2*a^4*b+a^2*b+b^3-(a*b^3)-3*a^2*b^2-(a^3*b) = 0
(a^5+a^3*b^2+2*a*b^2+2*a^4*b+a^2*b+b^3-(a*b^3)-3*a^2*b^2-(a^3*b))/(a*(a+b)^2) = 0
(a^5+a^3*b^2+2*a*b^2+2*a^4*b+a^2*b+b^3-(a*b^3)-3*a^2*b^2-(a^3*b))/(a*(a+b)^2) = 0 // * a*(a+b)^2
a^5+a^3*b^2+2*a*b^2+2*a^4*b+a^2*b+b^3-(a*b^3)-3*a^2*b^2-(a^3*b) = 0
x belongs to the empty set
| 4y=4(-x+8) | | 20+1.25x=2.5x | | 8ln(5x)=24 | | 1/4+1/3N=1/2 | | -x+-3.75=-2 | | 12x+(-4y)-12x+12y=-24-6 | | -5(m-4)=3 | | 12(-x+y)=12(-2) | | 8x+4x-3=15x-3x-5+2 | | 2x(x+1)= | | -1(-12x+4y)=-1(6) | | t^2+28=0 | | -a^2+11a-24=0 | | 3x^2-6= | | 21+9x-6+(-9x)=3y-3y | | -3y=-3(3x+2) | | 5x+7y=34 | | 3y=3(3x+7) | | 4+4=-3+2x+23 | | 5x-4x+5=2(x+1)+3-x | | -2(14x+7y)=-2(49) | | -5(x+5)-28=-3 | | -3u^2-8u+3=0 | | 14(2x+y)=14(7) | | x/3-1/x=2/3 | | -20x+10y+20x+(-10y)=20-20 | | x/5-5/x=0 | | (7x^2-2)=16 | | 63+7y=0 | | -10(-2x+y)=-10(2) | | 4y^2-28y-32=0 | | 2y+7x=-14 |